![]() Print("Item\tWeight\tProfit Value\tFraction") Hey guys welcome to this channel - Tricky mood- Here I will help you, finding your right paths, career options, soft skills and will also help you l. #Putting items of higher profit value per weight in sack Order= #order list contains list index of object in decreasing order of profit value per weight #Creating sequence for putting objects in the sack #Calculating profit value per weight value for objects #Initializing total weight in sack as wt and maximum profit value as max_profit We use a recursive approach as follows, find the item of median value, which can be done in linear time as shown in chapter 9. First compute the value of each item, defined to be its worth divided by its weight. Weight=list(map(int, input("Enter weight of items: ").split())) Show how to solve the fractional knapsack problem in O (n) O(n) time. Explain how to solve the fractional knapsack problem (the linear relaxation of the knapsack problem, i.e. Profit=list(map(int, input("Enter profit value of items: ").split())) If an item can not be put as a whole, put a suitable fraction of it so that we will get the maximum total profit. Proof: First show that as much as possible of the highest value/pound item must be included in the. Fractional knapsack is solved using dynamic programming.
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